3x^2-(3x+2)(x-1)=8

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Solution for 3x^2-(3x+2)(x-1)=8 equation: 


Simplifying
3x2 + -1(3x + 2)(x + -1) = 8

Reorder the terms:
3x2 + -1(2 + 3x)(x + -1) = 8

Reorder the terms:
3x2 + -1(2 + 3x)(-1 + x) = 8

Multiply (2 + 3x) * (-1 + x)
3x2 + -1(2(-1 + x) + 3x * (-1 + x)) = 8
3x2 + -1((-1 * 2 + x * 2) + 3x * (-1 + x)) = 8
3x2 + -1((-2 + 2x) + 3x * (-1 + x)) = 8
3x2 + -1(-2 + 2x + (-1 * 3x + x * 3x)) = 8
3x2 + -1(-2 + 2x + (-3x + 3x2)) = 8

Combine like terms: 2x + -3x = -1x
3x2 + -1(-2 + -1x + 3x2) = 8
3x2 + (-2 * -1 + -1x * -1 + 3x2 * -1) = 8
3x2 + (2 + 1x + -3x2) = 8

Reorder the terms:
2 + 1x + 3x2 + -3x2 = 8

Combine like terms: 3x2 + -3x2 = 0
2 + 1x + 0 = 8
2 + 1x = 8

Solving
2 + 1x = 8

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 1x = 8 + -2

Combine like terms: 2 + -2 = 0
0 + 1x = 8 + -2
1x = 8 + -2

Combine like terms: 8 + -2 = 6
1x = 6

Divide each side by '1'.
x = 6

Simplifying
x = 6

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